问题
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如果曲线y=f(x)在点(x,y)处的切线斜率与x2成正比,并且此曲线过点(1,-3)和(2,11),则此曲线方程
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曲面z=1-x2-y2在点(1/2 1/2 1/2)处的切平面方程是:A.x+y+z-3/2=0
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设曲线y=f(x)上任一点(x y)处的切线斜率为(y/x)+x2 且该曲线经过点(1 1/2)。 (1)求函数y
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曲线y=e^x在点(0 1)处的切线方程是_____。
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设函数y=y(x)满足微分方程y-3y+2y=2ex 其图形在点(0 1)处的切线与曲线y=x2-x+1在该点处的切线重
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如果曲线y=f(x)在点(x y)处的切线斜率与x2成正比 并且此曲线过点(1 -3)和(2 11) 则此曲线方程
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